If Rn- x-1-n- x- 1-n then R5- R15-

The correct option is A R_5 R_5 = x: 1/5 lt; x lt; 1/5 #160; And R_15 = x: 1/15 lt; x lt; 1/15 But, #160; 1/15 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Definition of Relations

If Rn= x:-1...

Question

If $R_{n} = {x : \frac{- 1}{n} < x < \frac{1}{n}}$ then $R_{5} \cup R_{15} =$ ________

R_{5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

R_{15}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R_{20}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

1 + \frac{1}{r} + \frac{1}{r^{4}} + \frac{1}{r^{9}} + \frac{1}{r^{16}} + \dots = 1 + \frac{1}{r -} \frac{r}{r^{3} + 1 -} \frac{r^{3}}{r^{5} + 1 -} \frac{r^{5}}{r^{7} + 1 -} \dots

C_{1}, C_{2}, C_{3}, C_{4}, C_{5}

r_{1}, r_{2}, r_{3}, r_{4}, r_{5}

(r_{1} < r_{2} < r_{3} < r_{4} < r_{5})

C_{i}

C_{i} + 1

i = 1, 2, 3, 4

L_{1}

L_{2}

r_{1} = 2

r_{5} = 32

r_{3}

R_{1}, R_{2}, R_{3}, R_{4}

R_{5}

10 \sum r = 0 (\frac{10}{r}) (\frac{15}{14 - r})

1 + r + r^{2} + r^{3} + . . . . . . . + r^{n} = (1 + r) (1 + r^{2}) (1 + r^{4}) (1 + r^{8})

Join BYJU'S Learning Program