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Question

If R={(x,y):x,yZ,x2+y24} is a relation in Z then domain D is

A
{2,1,0,1,2}
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B
{2,1,0}
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C
{0,1,2}
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D
None of these
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Solution

The correct option is C {2,1,0,1,2}
Relation Z consists of all the integral points inside and on the circle of radius 2 and center (0,0).

For all the points (x,y) which lie inside and on the circle xϵ[2,2] and yϵ[2,2]. Hence the domain is the integer values of x i.e 2,1,0,1,2.

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