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Question

If secα=23 then find the value of 1cosecα1+cosecα where α is in IV quadrant.

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Solution

Solution Rightarrow Given secα=23
α in 4th quadrant
To find 1cscα1+cscα=σ
secα=23
cscα=ACAB
=21=2
As α is in 4th quadrant. And in 4th quadrant csc is ve
cscα=2
Put cscα in 1cscα1+cscα
1cscα1+cscα=1(2)1+(2)=1+212
=31=3

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