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Byju's Answer
Standard XII
Mathematics
Domain
If sec α = ...
Question
If
s
e
c
α
=
2
√
3
then find the value of
1
−
c
o
s
e
c
α
1
+
c
o
s
e
c
α
where
α
is in IV quadrant.
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Solution
Solution
R
i
g
h
t
a
r
r
o
w
Given
sec
α
=
2
√
3
α
in
4
t
h
quadrant
To find
→
1
−
csc
α
1
+
csc
α
=
σ
⇒
sec
α
=
2
√
3
csc
α
=
A
C
A
B
=
2
1
=
2
As
α
is in
4
t
h
quadrant. And in
4
t
h
quadrant
csc
is
−
v
e
∴
csc
α
=
−
2
⇒
Put
csc
α
in
1
−
csc
α
1
+
csc
α
∴
1
−
csc
α
1
+
csc
α
=
1
−
(
−
2
)
1
+
(
−
2
)
=
1
+
2
1
−
2
=
3
−
1
=
−
3
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