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Byju's Answer
Standard XII
Mathematics
Properties Derived from Trigonometric Identities
If sin -1 x...
Question
If
sin
−
1
x
5
+
c
o
s
e
c
−
1
5
4
=
π
2
, then
x
is equal to:
A
1
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B
4
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C
3
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D
5
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Solution
The correct option is
A
3
sin
−
1
x
5
+
c
o
s
e
c
−
1
5
4
=
π
2
⇒
sin
−
1
x
5
+
sin
−
1
4
5
=
π
2
⇒
sin
−
1
x
5
=
π
2
−
sin
−
1
4
5
=
cos
−
1
4
5
⇒
x
=
5
sin
cos
−
1
4
5
=
5
sin
sin
−
1
3
5
=
3
Suggest Corrections
1
Similar questions
Q.
If
sin
−
1
(
x
5
)
+
c
o
s
e
c
−
1
(
5
4
)
=
π
2
, then the value of
x
.
Q.
If
sin
−
1
(
1
−
x
)
−
2
sin
−
1
x
=
π
2
, then
x
is equal to
Q.
Assertion :
cosec
−
1
(
3
/
2
)
+
cos
−
1
(
2
/
3
)
−
2
cot
−
1
(
1
/
7
)
−
cot
−
1
7
is equal to
cot
−
1
7
Reason:
sin
−
1
x
+
cos
−
1
x
=
π
/
2
,
tan
−
1
x
+
cot
−
1
x
=
π
/
2
,
cosec
−
1
x
=
sin
−
1
(
1
/
x
)
,
cot
−
1
(
1
/
x
)
=
tan
−
1
(
x
)
,
cot
−
1
(
x
)
=
tan
−
1
(
1
/
x
)
Q.
I
f
4
s
i
n
−
1
x
+
c
o
s
−
1
x
=
π
,
then x is equal to
Q.
Inverse circular functions,Principal values of
s
i
n
−
1
x
,
c
o
s
−
1
x
,
t
a
n
−
1
x
.
t
a
n
−
1
x
+
t
a
n
−
1
y
=
t
a
n
−
1
x
+
y
1
−
x
y
,
x
y
<
1
π
+
t
a
n
−
1
x
+
y
1
−
x
y
,
x
y
>
1
.
(a)
s
i
n
−
1
(
3
x
/
5
)
+
s
i
n
−
1
(
4
x
/
5
)
=
s
i
n
−
1
x
(b)
c
o
s
−
1
x
+
s
i
n
−
1
(
1
2
x
)
=
π
6
(c) If
a
≤
t
a
n
−
1
(
1
−
x
1
+
x
)
≤
b
where
0
≤
x
≤
1
then
(
a
,
b
)
=
(a)
(
0
,
π
)
(b)
(
0
,
π
/
4
)
(c)
(
−
π
/
4
,
π
/
4
)
(d)
(
π
/
4
,
π
/
2
)
(d) If
a
≤
(
s
i
n
−
1
x
)
3
+
(
c
o
s
−
1
x
)
3
≤
b
then (a,b) is equal to
(
π
3
32
,
7
π
3
8
)
.
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