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Question

If sin2A+sin2B+sin2C=9/4, then

A
A+B=C
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B
A+B+C=0
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C
A=B=C=60
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D
A+B=90C
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Solution

The correct option is C A=B=C=60
Given equation

sin2A+sin2B+sin2C=94

Put A=B=C=60

sin260+sin260+sin260

3×(32)2

3×34=94

A=B=C=60

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