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Question

If sin2θ1+sin2θ2+...+sin2θn=0 then find the minimum value of cos2θ1+cos2θ2+...+cos2θn

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Solution

Given, sin2θ1+sin2θ2+...+sin2θn=0

θ1,θ2...θn=0

cos2θ1,cos2θ2,...cos2θn=1

cos2θ1+cos2θ2+...+cos2θn=n

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