Question

If $sin(A+B)=\frac{\sqrt{3}}{2}$ and $sinB=\frac{1}{2}$ then A is

Answer 1

Given, $sinB=\frac{1}{2}$
$sinB=sin30$
$B={30}^{\circ }$
Also, $sin(A+B)=\frac{\sqrt{3}}{2}$
$sin(A+B)={60}^{\circ }$
$A+B={60}^{\circ }$
$A+30=60$
$A={30}^{\circ }$