Question

If $\sin A=\cos A$ and A is acute $\tan A-\cot A$ is equal to

• A. 2
• B. 1
• C. $\frac{1}{2}$
• D. 0

Answer 1

The correct option is D 0

$\sin A=\cos A$

$\Rightarrow \frac{\sin A}{\cos A}=1$

$\Rightarrow \tan A=1$

$\Rightarrow A=45°$

$\therefore \tan A-\cot A=\tan 45°-\cot 45°=1-1=0$

Hence, the answer is $0.$