If sinA=12,cosB=1√2 then the value of (A+B) is
If sinA=12 and cosB=1√2, then find the value of (A+B).
Given that sinA=12 and cosB=1√2, then find the value of (A+B).
Given that sin A=12 and cosB=1√2, then the value of (A + B) is:
Given that sin A = 12 and cos B = 1√2, then the value of (A + B) is ____. (Here, 0<A+B≤90∘)
Given that sin A= 12 and cosB =1√2, then find the value of (A+B) (where A and B are acute angles).