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Question

If sin(A+B)=32 and cot(AB)=3 then find the value of B.

A
15
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B
30
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C
10
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D
20
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Solution

The correct option is A 15
Given, sin(A+B)=32
A+B=60o -(1)
And cot(AB)=3
AB=30o---- (2)
Subtracting eqn 2 from 1
2B=300
B=150

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