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Question

If sinθ+cosθ=p and secθ+cosecθ=q, 0θπ2, and q(p21)=X, then

A
X>2
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B
X2
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C
X>4
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D
X4
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Solution

The correct option is B X2
q(p21)=(secθ+cosecθ)((sinθ+cosθ)21)
=(secθ+cosecθ)(sin2θ+cos2θ+2sinθcosθ1)
=(secθ+cosecθ)(1+2sinθcosθ1) (Since, sin2θ+cos2θ=1)
=(1cosθ+1sinθ)(2sinθcosθ)
=2sinθ+2cosθ

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