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Question

If sinθ=12,tanθ=13, nI, then most general values of θ are:

A
2nπ+π6, nI
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B
2nπ+π4, nI
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C
2nπ+π3, nI
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D
2nπ+π2, nI
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Solution

The correct option is A 2nπ+π6, nI
sinθ=12=sinπ6
θ=π6,ππ6
and tanθ=13=tan(π6)
θ=π6,π+π6
Common value of θ is π6
General value of θ is 2nπ+π6,nI

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