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Question

If 19k=1(2)kk!(19k)!=λ19! then find λ.

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Solution

19k=1(2)kk!(19k)!=λ19!19k=119!(2)kk!(19k)!19!=λ19!19k=119Ck(2)k(1)19k19!=λ19!(2H)1919C019!=λ19!11=λλ=2

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