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Byju's Answer
Standard XII
Mathematics
Property 6
If ∑i=110sin-...
Question
If
10
∑
i
=
1
sin
−
1
x
i
=
5
π
, then the value of
10
∑
i
=
1
x
2
i
is
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Solution
Given :
10
∑
i
=
1
sin
−
1
x
i
=
5
π
⇒
sin
−
1
x
1
+
sin
−
1
x
2
+
⋯
+
sin
−
1
x
10
=
5
π
We know that,
sin
−
1
x
∈
[
−
π
2
,
π
2
]
∴
The above equation is valid only when
sin
−
1
x
i
=
π
2
⇒
x
i
=
1
∴
10
∑
i
=
1
x
2
i
=
10
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Property 6
Standard XII Mathematics
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