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Question

If 10i=1sin1xi=5π, then the value of 10i=1x2i is

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Solution

Given : 10i=1sin1xi=5π
sin1x1+sin1x2++sin1x10=5π
We know that, sin1x[π2,π2]
The above equation is valid only when sin1xi=π2xi=110i=1x2i=10

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