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Question

If 360k=1(1kk+1+(k+1)k)=a, then the value of 19a is

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Solution

Let Tk=1kk+1[k+k+1]
=k+1kkk+1
=1k1k+1
S=360k=1(1k1k+1)
=11361
=1119=1819=a19a=18

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