If -n-1100-n-n-1-n-1-n-k- then the value of 101 k is

Given: ∑_n=1^100[nn+1 n 1n]=k ⇒ k = [12 0]+[23 12]+...+[100101 99100] ⇒ k=100101 0 ∴ nbsp; 101k=100 ...

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Multinomial Expansion

If ∑n=1100[n/...

Question

If $100 \sum n = 1 [\frac{n}{n + 1} - \frac{n - 1}{n}] = k$ , then the value of $101 k$ is

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