If 44∑r=049−rC5=50Cx, then the value(s) of x is/are
A
6
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B
5
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C
44
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D
45
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Solution
The correct options are A6 C44 Given : 44∑r=049−rC5=50Cx Now, 44∑r=049−rC5=49C5+48C5+47C5+⋯+5C5=5C5+6C5+7C5+⋯+49C5=6C6+6C5+7C5+⋯+49C5(∵6C6=5C5)=49+1C6=50C6 Now, 50Cx=50C6⇒x=6,(50−6)∴x=6,44