If -n - 151nn - 1n - 2n - 3 - k3- then k is equal to

The correct option is A 55336 Hence, Option (A) is the correct answer. ...

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Laws of Exponents for Real Numbers

If ∑n = 151...

Question

If $5 \sum n = 1 \frac{1}{n (n + 1) (n + 2) (n + 3)} = \frac{k}{3}$ , then $k$ is equal to

\frac{55}{336}

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\frac{17}{105}

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\frac{1}{6}

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\frac{19}{112}

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Solution

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Similar questions

5 \sum n = 1 \frac{1}{n (n + 1) (n + 2) (n + 3)} = \frac{k}{3}

k

6

n - \frac{n (n - 1) (n - 2)}{⌊ 3} \cdot 3 + \frac{n (n - 1) (n - 2) (n - 3) (n - 4)}{⌊ 5} \cdot 3^{2} - . . . . .,

n - \frac{n (n - 1) (n - 2)}{⌊ 3} \cdot \frac{1}{3} + \frac{n (n - 1) (n - 2) (n - 3) (n - 4)}{⌊ 5} \cdot \frac{1}{3^{2}} - . . . . .,

\infty \sum n = 1 \frac{1}{(n + 1) (n + 2) (n + 3) . . . . (n + k)}

S_{n} = \sum_{r = 1}^{n} T_{r} = n (n + 1) (n + 2) (n + 3)

\sum_{r = 1}^{n} \frac{1}{T}

n \sum r = 1 t_{r} = \frac{n (n + 1) (n + 2) (n + 3)}{8}

n \sum r = 1 \frac{1}{t_{r}}

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