If k∑r=1r=12(n2+11n+30) is true for n∈N, then k=
(use principle of mathematical induction)
A
n+7
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B
n+6
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C
n+4
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D
n+5
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Solution
The correct option is Dn+5 12(n2+11n+30)=12(n+5)(n+6)
Here, 1+2+3+⋯+k=k(k+1)2
[from mathematical induction]
By replacing k by n+5, ∴1+2+3+⋯(n+4)+(n+5)=(n+5)(n+6)2 ∴k=(n+5)