If - r-1nTr-5n-2 and - r-1nTr2-an3-bn2-cn-d then the value of d-b-c

∑ _ r=1 ^ n T _ r =5n+2 T _ 1 =7 ∑ _ r=1 ^ 2 T _ r =12= gt; T _ 1 + T _ 2 =12 T _ 2 =5 Similarly T _ 3 =5, T _ 4 =5,.... T ...

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Summation by Sigma Method

If ∑ r=1nTr...

Question

If $n \sum r = 1 T_{r} = 5 n + 2$ and $n \sum r = 1 T_{r}^{2} = a n^{3} + b n^{2} + c n + d$ then the value of $d + b + c$

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n \sum s = 1 {s \sum r = 1 r} = a n^{3} + b n^{2} + c n

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n \sum r = 1 \frac{1}{t_{r}}

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