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Question

If nr=1tr=nk=1kj=1ji=1(2), then nr=11tr is

A
1n+1
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B
nn+1
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C
n+1n
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D
n+1
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Solution

The correct option is B nn+1
nr=1tr=nk=1kj=1ji=1(2)=nk=1kj=12j=nk=1k(1+k)tr=r(1+r)1tr=1r(r+1)=1r1r+1
Now nr=11tr
=1112+1213+1314+ +1n1n+1=11n+1=nn+1

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