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B
49
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C
36
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D
64
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Solution
The correct option is A 59 t54=a+53d=−64...........(1) t4=a+3d=61.........(2) Subtracting eq 1 and 2 50d=−125 d=−2.5 Substitute the value of d in eq 2 a=64−(3×−2.5) a=64+7.5=71.5 t10=a+9d ⇒71.5+(9×−2.5) ⇒71.5−22.5=49