Question

If $T=\frac{5}{9}(K-32)$ and if $T=290$, then $K=$

• A. $\frac{1738}{9}$
• B. $322$
• C. $490$
• D. $554$
• E. $\frac{2898}{5}$

Answer 1

The correct option is D $554$

$T=\frac{5}{9}(K-32)$

when $T=290$

$290=\frac{5}{9}(K-32)$

$\frac{290\times 9}{5}=K-32$

$58\times 9=K-32$

$K=58\times 9+32$

$K=522+32$

$K=554$