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B
nπ4
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C
2nπ
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D
None of these
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Solution
The correct option is Anπ tan3θ+tanθ=2tan2θ ⇒tan3θ−tan2θ=tan2θ−tanθ ⇒sin3θcos2θ−cos3θsin2θcos3θcos2θ=sin2θcosθ−cos2θsinθcosθcos2θ ⇒sinθcos3θ=sinθcos2θ ⇒sinθ=0 θ=nπ Ans: A