If tan A - B- prove that A-B- 90 -

Given, tan A= B tan A=tan(90 B) A=90^o B, ∴ #160;A+B=90^o ...

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Complementary Trigonometric Ratios

If tan A = ...

Question

If $tan A = cot B$ , prove that $A + B = 90^{\circ}$ .

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A + B = 90^{\circ}

A + B = 90^{\circ}

\sqrt{\frac{tan A tan B + tan A cot B}{sin A sec B} - \frac{{sin}^{2} B}{{cos}^{2} A}} = tan A

t a n A = cot B,

A + B = 90^{0}

tan A = cot B

A + B + 90

A + B = 90^{o}

\sqrt{\frac{t a n A t a n B + t a n A c o t B}{s i n A s e c B} - \frac{s i n^{2} B}{c o s^{2} A}} = t a n A

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