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Question

If tanα=mm1 , tanβ=12m1, then αβ=

A
π2
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B
π4
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C
π
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D
π6
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Solution

The correct option is B π4

tan(αβ)=tanαtanβ1+tanαtanβ
=mm112m11+m(m1)(2m1) Given tanα=mm1,tanβ=12m1
=2m2mm+12m2m2m+1+m
tan(αβ)=2m22m+12m22m+1=1
αβ=π4


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