Question

If $\tan \theta =\frac{4}{3}$, then what is the value of $\sqrt{\frac{1-\sin \theta }{1+\sin \theta }}$?

Answer 1

If $\tan \theta =\frac{4}{3}$

then

$\text{by using trigonometric ratio form , we get}$

$\sin \theta =\frac{4}{5}$

$\text{put the value of}$

$\sin \theta =\frac{4}{5}$

$\text{we get}$
$\therefore \sqrt{\frac{1-\sin \theta }{1+\sin \theta }}=\sqrt{\frac{1-\frac{4}{5}}{1+\frac{4}{5}}}=\sqrt{\frac{1}{9}}=\frac{1}{3}$