If $△ A B C$ is right angles at A then value of $tan B$ $tan C$ is

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\frac{1}{2}

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Solution

The correct option is C $1$
If $△ A B C$ is rightangle at A
Then $t a n B = \frac{A C}{B A}$ and $t a n C = \frac{B A}{A C}$
$∴ t a n B \times t a n C = \frac{A C}{B A} \times \frac{B A}{A C} = 1$

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