If u-a-b-v-a-b and - a - - b -2- then - u- v - is equal to

The correct option is C 2√( [ 16 ( a· b )^2 ]) u× v = (a b)× (a+b) = 2(a× b) ∴ |u× v | =2|a||b|sinθ =8sinθ = 8√(1 cos^2θ) = 8√(1 (a· b|a| ...

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Applications of Cross Product

If u=a-b,v=...

Question

If $u = a - b, v = a + b$ and $| a | = | b | = 2,$ then $| u \times v |$ is equal to

2 \sqrt{[16 - {(a \cdot b)}^{2}]}

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\sqrt{[16 - {(a \cdot b)}^{2}]}

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2 \sqrt{[4 - {(a \cdot b)}^{2}]}

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[4 - {(a \cdot b)}^{2}]

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| \to a \times \to b |^{2} + (\to a \cdot \to b)^{2} = 144

| \to a | = 4

| \to b | =

(¯ ¯ ¯ a \times ¯ ¯ b)^{2} + (¯ ¯ ¯ a \cdot ¯ ¯ b)^{2} = 144

| a | = 4

| b |

{{| a \times b |}^{2} + {(a \cdot b)}^{2}} \div (a^{2} b^{2})

¯ ¯ ¯ a = 2 \to i + 2 \to j + ¯ ¯ ¯ k, ¯ ¯ b = 5 \to i + ¯ j + 2 ¯ ¯ ¯ k

| ¯ ¯ ¯ a \times ¯ ¯ b |^{2} + (¯ ¯ ¯ a \cdot ¯ ¯ b)^{2} =

If $(\to a \times \to b)^{2} + (\to a . \to b)^{2} = 144$ and $| \to a |$ , then $| \to a |$ =

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