If $v_{o r d i n a r y} > v_{e x t r a o r d i n a r y}$ the crystal is said to be

positive

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negative

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neutral

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birefringent

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Solution

The correct options are
A positive
D birefringent
As there are two types of velocities then the crystal is $B i r e f r i n g e n t$ and as $V_{o r d i n a r y} > V_{e x t r a o r d i n a r y}$ it is $p o s i t i v e$
option $A$ and $D$ are correct

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