If →a and →b are two vectors then the value of (→a+→b)×(→a−→b) is:
A
2(→b×→a)
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B
−2(→b×→a)
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C
→b×→a
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D
→a×→b
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Solution
The correct option is A2(→b×→a) (→a+→b)×(→a−→b)=→a×(→a−→b)+→b×(→a−→b)
=→a×→a−→a×→b+→b×→a−→b×→b
Now, cross product of a vector with itself is zero (θ = 0, thus sinθ = 0) Also, →a×→b=−(→b×→a) Hence, given equation becomes 0+→b×→a+→b×→a+0 which gives 2(→b×→a)