If →A,→B,→C are three non-coplanar vectors, then value of →A.→B×→C→C×→A.→B+→B.→A×→C→C.→A×→B
A
-1
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B
0
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C
1
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D
2
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Solution
The correct option is B 0 Since →A,→B,→C are non-coplanar, we have [→A→B→C]≠0 Also →A.→B×→C=[→A→B→C], →C×→A.→B=[→C→A→B]=[→A→B→C] [→B.→A×→C]=[→B→A→C]=−[→A→B→C] and →C.→A×→B=[→C→A→B]=[→A→B→C] Hence →A.→B×→C→C×→A.→B+→B.→A×→C→C.→A×→B=1−1=0