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Question

If x1,x2,x3,.... are n values of the variable x, then mathematical averages, Arithmetic Mean (A.M.), Geometric Mean (G.M) and Harmonic Mean (H.M) are count by the following formulas's.

A.M.=x1+x2+x3+...+xnn=1n{ni=1x1}x1>0

G.M.=(x1x2...xn)1/n if each x1(i=1,2,....,n) is positive and

H.M=n1x1+1x2+...+1xn=11nni=1(1x1)

* In case of frequency distribution x/f1(i=1,2,...,n) where f1 is the frequency of the variable xr then the calculation of A.M.is counted as A.M=ni=1f1x1/NwhereN=f1+f2....+fn

** If w1,w2,....,wn be the weight assigned to the n values

x1,x2,....,xn then weighted A.M is counted by ni=1w1x1ni=1w1

*** if G1,G2 are the G. M's of two series of sizes n1 & n2 respectively, then the geometric mean (G M.) of the combined series is counted by log(G.M)=n1logG1+n2logG2n1+n2


On the basis of above information answer the following questions,The mean of a set of n numbers is ¯x If each number is divided by 4 then new mean is

A
¯x
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B
¯x+4
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C
¯x4
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D
4¯x
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Solution

The correct option is C ¯x4
Let the n numbers be x1, x2, ..., xn then ¯x=ni=1xin
When each number be divided by 4 then new numbers be x14,x24, ..., xn4
New mean =x14+x24+...+xn4n
14[x1+x2+...+xnn]
=14{1nni=1xi} =¯x4

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