Question

If $x^2-\frac{x}{12}-\frac{1}{12}=0$, then value of $x$ is equal to

• A. $\frac{1}{3},-\frac{1}{4}$
• B. $\frac{2}{7},-\frac{2}{9}$
• C. $\frac{5}{8},-\frac{1}{8}$
• D. None of these

Answer 1

The correct option is A $\frac{1}{3},-\frac{1}{4}$

Multiplying the entire equation by $12$, we get
$12x^2-x-1=0$
$12x^2-4x+3x-1=0$
$4x(3x-1)+1(3x-1)=0$
$(4x+1)(3x-1)=0$

$x=\frac{-1}{4}$ and $x=\frac{1}{3}$