If x2 - 1-x2 - A and x - 1-x - B then least value of A-B is

The correct option is B 2√(2) AB=x^2+1x^2 ( x 1/x )= ( x 1x )^2+2 ( x 1/x ) = ( x 1x )+2 ( x 1x ) =p+2p where p=x 1x ≥√(2) ...

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AM,GM,HM Inequality

If x2 + 1/x...

Question

If $x^{2} + \frac{1}{x^{2}} = A$ and $x - \frac{1}{x} = B$ then least value of $\frac{A}{B}$ is

2

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\sqrt{2}

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- \sqrt{2}

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2 \sqrt{2}

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Solution

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Similar questions

f (x) = x^{2} + a

x \leq 0

= 2 \sqrt{1 + x^{2}} + b

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f (- 1) = 2

f

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(a, b) \equiv

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x - \frac{1}{x} = B

\frac{A}{B}

x^{2} + 4 x + a

x^{2} + 4 x + b

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A + B + C =

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