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Question

If x2+px+1 is a factor of ax3+bx+c, then

A
a2+c2=ab
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B
a2c2=ab
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C
a2c2=ab
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D
none of these
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Solution

The correct option is C a2c2=ab
As x2+px+1 is a factor of ax3+bx+c=0
Then ax3+bx+c=(x2+px+1)(ax+c)
The other factor is of first degree whose coefficients are chosen keeping in view the coefficient of x3 and constant term in cubic,
Comparing the coefficient of x2
ap+c=0p=ca ...(1)
And comparing the coefficients of x
a+cp=b (2)
From (1) and (2), we have
a+c(ca)=b
a2c2=ab.
Hence, option 'C' is correct.

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