The correct option is C a2−c2=ab
As x2+px+1 is a factor of ax3+bx+c=0
Then ax3+bx+c=(x2+px+1)(ax+c)
The other factor is of first degree whose coefficients are chosen keeping in view the coefficient of x3 and constant term in cubic,
Comparing the coefficient of x2
ap+c=0∴p=−ca ...(1)
And comparing the coefficients of x
a+cp=b (2)
From (1) and (2), we have
a+c(−ca)=b
⇒a2−c2=ab.
Hence, option 'C' is correct.