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Question

If x2+y2=25 and xy=12, then the value of x−1+y−1 is

A
125
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B
712
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C
712
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D
Both (B) and (C)
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Solution

The correct option is D Both (B) and (C)
Given,
x2+y2=25
xy=12
We, know
(x+y)2=x2+y2+2xy
=25+2×12
=49
x+y=±7
Now, x1+y1 =1x+1y
=x+yxy
=712 or, 712

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