If x2+y2+2x+1=0, and x=−1, then the value of x2+y2 is___
Given:
x2+y2+2x+1=0
If x=−1 then,
x2+y2+2x+1=0 put value x=−1
⇒x2+y2−1=0
⇒x2+y2=1
Hence, Option B is correct.
The equation of a circle which cuts the three circles
x2 + y2 − 3x − 6y + 14 = 0,
x2 + y2 − x − 4y + 8 = 0
x2 + y2 + 2x − 6y + 9 = 0
orthogonally is –––––––––––––––