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Question

If x=7+43,y=743 find the value of 1x2+1y2

A
194
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B
198
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C
212
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D
318
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Solution

The correct option is A 194
We have, x=7+43 So,
x2=1(7+43)2=149+48+563=(97563)(97+563)(97563)=9756394099408=97563

Now, y=743 So,
y2=1(743)2=149+48563=(97+563)(97+563)(97563)=97+56394099408=97+563

So, x2+y2=97563+97+563=194

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