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Question

If x=acos3θ and y = b sin3θ, then the value of (xa)2/3+(yb)2/3 is

A
1
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B
-2
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C
2
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D
-1
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Solution

The correct option is A 1
The value of (xa)23+(yb)23 is
=(3acos3θa)2+(3bsin3θb)2
=(sinθ)2+(cosθ)2=sin2θ+cos2θ=1

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