If x-at2-y-2at then d2y-dx2-

The correct option is D 1/2at^3 x=at^2 ,y=2at ⇒dx/dt=2at , dy/dt=2a ⇒dy/dx=1/t ⇒ ( d^2y/dx^2 )= 1/t^2dtdx = 1/t^2× 2at = ...

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Property 2

If x=at2,y=...

Question

If $x = a t^{2}, y = 2 a t$ then $\frac{d^{2} y}{d x^{2}} =$

- \frac{1}{t^{2}}

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\frac{1}{2 a t^{3}}

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- \frac{1}{t^{3}}

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- \frac{1}{2 a t^{3}}

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Solution

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Similar questions

x = a t^{2}, y = 2 a t,

\frac{d^{2} x}{d y^{2}} =

x = a t^{2}

y = 2 a t

\frac{d^{2} y}{d x^{2}}

t = \frac{1}{2} i s

x = a t^{2}, y = 2 a t

\frac{d^{2} y}{d x^{2}}

x = a t^{2}

y = 2 a t

\frac{d^{2} y}{d x^{2}}

t = \frac{1}{2}

x = a t^{2}, y = 2 a t

\frac{d^{2} y}{d x^{2}} = \frac{- 1}{2 a t^{2}}

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