If x - 1-5-2-6 then find the value of x2 - 10x -

The correct option is B 1 1 5+2√( 6 ) #160; = 5 2√( 6 ) #160; (5+2√( 6 ) )(5 2√( 6 ) ) = 5 2√( 6 ) #160; 25 24 =5 2√( 6 ) So, x^2 ...

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If x = 1/5+...

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If $x = \frac{1}{5 + 2 \sqrt{6}}$ then find the value of $x^{2} - 10 x =$

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Similar questions

x = 5 + 2 \sqrt{6}

y = 5 - 2 \sqrt{6}

\frac{1}{x^{2}} + \frac{1}{y^{2}}

x^{2} + \frac{1}{x^{2}}

x = 5 + 2 \sqrt{6}

x = 5 - 2 \sqrt{6},

x^{2} + \frac{1}{x^{2}}

x = 5 - 2 \sqrt{6},

{(x - \frac{1}{x})}^{2}

If x varies directly with y,

a n d x_{1} = \frac{1}{5}, y_{1} = \frac{1}{6}, x_{2} = \frac{2}{5}, then find the value of y_{2} .

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