If x-1-x-2- then x2-1-x2 is equal to -

The correct option is A 2 Given, x+ 1x=2 .On squaring both side, we get, (x+1x)^2=4 .We know, (a+b)^2=a^2+b^2+2ab . x^2+(1x)^2+2( ...

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(a-b)^2 Expansion and Visualisation

If x+1/x=2,...

Question

If $x + \frac{1}{x} = 2$ , then $x^{2} + \frac{1}{x^{2}}$ is equal to :

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Solution

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Similar questions

x + \frac{1}{x} = 2

\neq

x^{2} + \frac{1}{x^{2}}

x + \frac{1}{x} = 2

x^{2} + \frac{1}{x^{2}}

x + \frac{1}{x} = 2, x \neq 0

x^{2} + \frac{1}{x^{2}}

α \in (0, \frac{π}{2})

\sqrt{x^{2} + x} + \frac{{tan}^{2} α}{\sqrt{x^{2} + x}}

(x \neq 0, - 1)

y = {tan}^{- 1} (\frac{1}{1 + x + x^{2}}) + {tan}^{- 1} (\frac{1}{x^{2} + 3 x + 2}) + {tan}^{- 1} (\frac{1}{x^{2} + 5 x + 6}) + . . . . +

n

\frac{d y}{d x}

x = 0

n = 1

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