Question

If $x+\frac{1}{x}=5$, then $\frac{2x}{3x^2-5x+3}$ is equal to

• A. $5$
• B. $\frac{1}{5}$
• C. $3$
• D. $\frac{1}{3}$

Answer 1

Answer: (B)

$\frac{1}{5}$

$\therefore$ $x+\frac{1}{x}=5$

$\Rightarrow$ $x^2-5x+1=0$

$\therefore$ Given Exp. = $\frac{2x}{3x^2-5x+3}$

$=\frac{2x}{3x^2-15x+3+10x}$

$=\frac{2x}{0+10x}=\frac{1}{5}$