Question

if $x=\frac{y}{(1+p{)}^q}$ , then q is equal to

• A. $\log \left[\frac{\frac{y}{x}}{1+p}\right]$
• B. $\frac{\log \left(\frac{y}{x}\right)}{\log (1+p)}$
• C. $\frac{\log (y-x)}{\log (1+p)}$
• D. $\frac{\log (y+x)}{\log (1+p)}$

Answer 1

The correct option is B $\frac{\log \left(\frac{y}{x}\right)}{\log (1+p)}$

$x=\frac{y}{(1+p{)}^q}$ can be written as

$=(1+p{)}^q=\frac{y}{x}$

taking log both side, we have

$qlog(1+p)=log\frac{y}{x}$

$q=\frac{log\frac{y}{x}}{log(1+p)}$