Question

If $x=m+1$ and $\frac{1}{3}(6x-3)-(8-3x)=11;$ find the value of $m$.

• A. $m=7$
• B. $m=6$
• C. $m=2$
• D. $m=3$

Answer 1

The correct option is D $m=3$

Given, $\frac{1}{3}(6x-3)-(8-3x)=11$

As L.C.M. is $3$, we have

$6x-3-24+9x=33$

$\Rightarrow 15x-27=33$

$\Rightarrow 15x=60$

$\Rightarrow x=4=3+1$

Thus comparing this with $x=m+1$, we get value of $m$ as $3$.