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Question

If x=rsinθcosϕ, y=rsinθsinϕ and z=rcosθ, then the value of x2+y2+z2 is independent of:

A
θ,ϕ
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B
r,θ
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C
r,ϕ
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D
r
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Solution

The correct option is D θ,ϕ
Given, x=rsinθcosϕ, y=rsinθsinϕ and z=rcosθ

Therefore, x2+y2+z2
=(rsinθcosϕ)2+(rsinθsinϕ)2+(rcosθ)2

=r2sin2θcos2ϕ+r2sin2θsin2ϕ+r2cos2θ

=r2sin2θ(cos2ϕ+sin2ϕ)+r2cos2θ
=r2sin2θ+r2cos2θ

=r2(sin2θ+cos2θ)

=r2

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