If x-sin -12t-1-t2 and y- -2-cos -1t- then find the value of d2y-dx2 at t-3-

y= π/2 cos ^ 1t=sin ^ 1t ∴ t= sin y ∴ x= sin ^ 1sin 2y =2y ∴dy/dx= 1/2 and nbsp; nbsp;d^2y/dx^2=0∀ x and t . ...

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Formation of a Differential Equation from a General Solution

If x=sin -1...

Question

If $x = {sin}^{- 1} 2 t \sqrt{1 - t^{2}}$ and $y = \frac{π}{2} - {cos}^{- 1} t,$ then find the value of $\frac{d^{2} y}{d x^{2}}$ at $t = \frac{π}{3} .$

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\frac{d^{2} y}{{d x}^{2}}

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