If xsin 45-cos 45-tan 260- 230-cosec230- then x -

The correct option is C 14/3 x ( 1/√(2) ) ( 1/√(2) )+ ( √(3) )^2= ( 2/√(3) )^2 ( 2 )^2 or #160;x=14/3 ...

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If xsin 45∘...

Question

If $x sin 45^{\circ} cos 45^{\circ} + {tan}^{2} 60^{\circ} = {sec}^{2} 30^{\circ} c o s e c^{2} 30^{\circ}$ then x =

10/3

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14/3

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16/3

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Solution

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If $x s i n 45^{\circ} c o s^{2} 60^{\circ} = \frac{t a n^{2} 60^{\circ} c o s e c 30^{\circ}}{s e c 45^{\circ} c o t^{2} 30^{\circ}}$ , then x =

{tan}^{2} 45^{\circ} - {cos}^{2} 30^{\circ} = x sin 45^{\circ} cos 45^{\circ}

{tan}^{2} 45^{\circ} - {cos}^{2} 30^{\circ} = x sin 45^{\circ} cos 45^{\circ}

x =

\frac{1}{2}

- \frac{1}{2}

- \frac{1}{2}

\frac{1}{2}

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